Question 731943
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A 340 meter long train is accelerating from rest at 6 meter/second square. 
With the start of motion, a man standing at the front end of the train, projects a ball upwards 
at a velocity of 50 meters/second. Do calculaions to decide if the ball will fall back on the train 
or will miss it.
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        I will solve the problem as physicists do.



<pre>
The ball will move up  during  {{{v/g}}} = {{{50/10}}} = 5 seconds.


Next 5 seconds the ball will fall down from the most upper level to the ground.


So, the train has 10 seconds to move forward while the ball is in the air.


During 10 seconds, the train will move forward  {{{(at^2)/2}}} = {{{(6*10^2)/2}}} = 300 meters.


Hence, the ball will fall back on the train.
</pre>

Solved.