Question 903490
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Two cyclists leave towns 90mi  apart at the same time and travel toward each other. 
One cyclist travels 8 miles per hour  faster than the other. 
If they meet in 3  hours, what is the rate of each cyclist?
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<pre>
Let x be the speed of the slower cyclist, in miles per hour.
Then the speed of the faster cyclist is (x+8) miles per hour.


The sum of their distances must equal the total distance they were
apart when they started.

            3x + 3(x+8) = 90
           3x + 3x + 24 = 90 
                6x + 24 = 90
                     6x = 66
                      x = {{{66/6}}} = 11 mph.

The slower cyclist was going 11 mph and the faster one was going
8 mph faster or 19 mph.
</pre>

Solved correctly.