Question 732140
.
Divide 56 Into Two Parts Such That Three Times The First Parts Exceeds One Third Of The Second By 48. 
The Parts Are
~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
Let x be first part; then the second part is (56-x).


The imposed condition is

    3x - {{{(56-x)/3}}} = 48.


To solve this equation, multiply all the terms by 3

    9x - (56-x) = 48*3,

    9x + x = 144 + 56,

      10x  =    200,

        x  =    200/10 = 20.


<U>ANSWER</U>.  The parts are 20 and 56-20 = 36.
</pre>

Solved.


The answer in the post by @lynnlo is incorrect.


Simply ignore his post.