Question 733415
<pre>
"Two cyclists travel on a straight path towards each other each travelling at a constant speed of 10mph.
The cyclists start of 10 miles apart. If a fly starts at the front of one cyclists and keeps flying
backwards and forward until the two cyclists crash, how far will the fly fly give that the fly travels at 1mph?"

I'm not sure where to start... please could you give a brief explanation of how to work it out if possible.
Thanks if you can help

The problem should NOT READ, "flying backwards and forward", BUT <font color =red><font size = 4><b> "flying BACK and FORTH"</font></font></b>, instead.  

Distance cyclists are apart: 10 miles
Speed each cyclist travels: 10 mph

Let time taken for cyclists to meet, be T
Then we get the following DISTANCE equation: 10T + 10T = 10
                                                   20T = 10
                 Time taken for cyclists to meet, or T = {{{10/20 = 1/2}}}hr
Time fly spent flying is ALSO {{{1/2}}}hr

Since fly spent {{{1/2}}}hr flying, at 1 mph, distance fly flew = {{{highlight_green(matrix(1,3, (1/2)1, "=", highlight(matrix(1,2, 1/2, mile))))}}}.</pre>