Question 1210478
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Let XYZ be a triangle, and let XP, XQ, XR be the altitude, angle bisector, and median from X, respectively. 
If angle YQZ = 90^\circ and angle ZQX = 22^\circ, then what is the measure of angle RZP in degrees?
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The problem is posed incorrectly.


Indeed, it says (states) that angle YQZ is 90 degrees.


But it is impossible, since the point Q lies on the side YZ, because Q is the base of the 
angle bisector XQ, issued from vertex X opposite to side YZ of the triangle.


So, again, the problem is posed incorrectly, is self-contradictory  
and describes the situation which never may happen.


What is written further in the post by @CPhill as a solution, 
it does not matter, because it is non-sensical gibberish.



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<H3>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;The problem is refuted.</H3>
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