Question 732971
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{{{highlight(cross(In))}}} <U>If</U> a single die is rolled one time. Determine the probability of rolling an odd number or a number greater than four.
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<pre>
The space of events consists of 6 events '1', '2', '3', '4', '5', '6' with the probability 1/6 each.


The favorable events are '1', '3', '5', '6'. Their cardinality is 4 (four).


Therefore, the probability under the problem's question is


    P = {{{favorable/total}}} = {{{4/6}}} = {{{2/3}}}.   <U>ANSWER</U>
</pre>

Solved.