Question 733683
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Dermont and tony are competing to see whose house is the tallest. 
Early in the afternoon, Tony, who is 4 feet tall, measured his shadow to be 9.6 inches 
and the shadow of his house to be 62.4 inches. 
Later in the day, Dermont, who is five feet all, measured his shadow to be 15.6 inches 
and the shadow of his house to be 62.4 inches. Who lives in the taller house?
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<pre>
We assume that all measurements relate to horizontal ground surface.


If so, then we write the proportion for the Tony's house height 'T'

    {{{T/62.4}}} = {{{4/9.6}}},


which gives  the Tony's house height  T = {{{(62.4*4)/9.6)}}} = 26 feet.



Next, we write the proportion for the Dermont's house height 'D'

    {{{D/62.4}}} = {{{5/15.6}}},


which gives  the Dermont's house height  D = {{{(62.4*5)/15.6)}}} = 20 feet.


<U>ANSWER</U>.  Tony's hous is taller.
</pre>

Solved.


The solution in the post by @lynnlo is incorrect.



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The fact that measurements for the height-shadow are made at the different time of the day
does not interfere to write the proportions as they are written in my solution.


The triangles that are similar and should be similar and whose similarity is used, 
remain similar at any time of measurements.