Question 736990
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There are 8 cars in a parking lot on a very cold day. 
Suppose the probability of any of them not starting is 0.13. 
What is the probability that exactly 2 of the cars will not start?
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There is no need to explain that this problem is on binomial distribution, 
since it is obvious.



<pre>
Here the number of trials is 8; the number of successful trials is 2;
the probability of the individual success is p = 0.13.


Use the standard formula on Binomial distribution

    P(n=8, k=2, p=0.13) = {{{C[8]^2*0.13^2*(1-0.13)^(8-2)}}} = {{{28*0.13^2*0.87^6}}} = 0.2052  (rounded).   <U>ANSWER</U>
</pre>

Solved.