Question 612274
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I have two algebra I word problems i need help setting up. I would like if you can explain the steps of setting up.
Here it is:
Problem #1
The length of a rectangle is 2 1/2 times its width. Its area is 90 square units. What are its dimensions? (Hint: length times width = area)
Let w= width in units.
L=(2 1/2)w= 5w/2 = length in units

The person who responded is WRONG!! Width is NOT 3 units!

As indicated by you, let width be w
Then length (L), as you stated is {{{2&1/2w}}}, or 2.5w
As it's given that area = 90 square units, we get: 2.5w(w) = 90
                                                     2.5w<sup>2</sup> = 90
                                                        {{{w^2 = 90/2.5}}}
                                                        {{{w^2 = 36}}}
                           Width of rectangle, or {{{highlight_green(matrix(1,6, w, "=", sqrt(36), "=", 6, units))}}}
                                          <font color = red><font size = 4><b>Length: 2.5(6) = 15 units</font></font></b></pre>