Question 748183
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Sketch the graph of f(x)= (3(x^2-4))/(x^2-1) give the x and y intercepts 
and the horizontal and vertical asymptotes
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<pre>
You get vertical asymptotes by equating the denominator to zero

    x^2 - 1 = 0.


From this equation, you find its roots  x = 1 and -1.

The equations of asymptotes are  x = 1  and  x = -1.



You get x- intercepts by equating the numerator to zero

    x^2 - 4 = 0.


From this equation, you find its roots  x = 2 and -2.

Thus, x-intercepts are  x = 2  and  x = -2.



You find y-intercept by taking x = 0 in the formula for the function, so, y-intercept is

    y = {{{(3*(0-4))/(0-1)}}} = {{{(-12)/(-1)}}} = 12.
</pre>

Solved.  All questions are answered.


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