Question 670863
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A bank contains 44 coins (nickels, dimes, quarters). There are twice as many dimes as nickels 
and 8 fewer nickels than quarters. How much money is in the bank?
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Let x be the number of nickels.

Then the number of dimes is 2x, according to the problem,

and the number of quarters is (x+8).


Having this, write equation for the total number of coins

    x + 2x + (x+8) = 44.    (here 44 is the given total number of coins).


Simplify this equation and find x

    4x + 8 = 44,

    4x = 44 - 8 = 36,

     x =36/4 = 9.


So, there are 9 nickels in the bank,  2*9 = 18 dimes and 9+8 = 17 quarters.


Now you can easily find the value of the bank

    5*9 + 10*18 + 17*25 = 650 cents,  or 6.50 dollars.


<U>ANSWER</U>.  The value of the bank is $6.50.
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