Question 670863
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I am not sure how to figure out a coin problem without how much it's worth for example: 
A bank contains 44 coins (nickles, dimes, quarters). There are twice as many dimes as nickles 
and 8 fewer nickles than quarters. How much money is in the bank?
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        I will give a simple,  straightforward,  short and instructive solution,

        using only one single equation in one single unknown.



<pre>
Let x be the number of nickels.

Then the number of dimes is 2x, according to the problem,

and the number of quarters is (x+8).


Having this, write equation for the total number of coins

    x + 2x + (x+8) = 44.    (here 44 is the given total number of coins).


Simplify this equation and find x

    4x + 8 = 44,

    4x = 44 - 8 = 36,

     x =36/4 = 9.


So, there are 9 nickels in the bank,  2*9 = 18 dimes and 9+8 = 17 quarters.


Now you can easily find the value of the bank

    5*9 + 10*18 + 17*25 = 650 cents,  or 6.50 dollars.


<U>ANSWER</U>.  The value of the bank is $6.50.
</pre>

Solved and explained in a simple and instructive way, using only one unknown,
and without introducing system of equation, which is not necessary here.



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I wrote this my solution as an alternative to the long, &nbsp;wordy solution by &nbsp;@Theo.


We live now at the time when every our solution, &nbsp;produced at this forum,
goes directly to the database for &nbsp;Artificial &nbsp;Intelligence.


So not tens, &nbsp;but tens millions students/readers will read them.


While &nbsp;10 &nbsp;years ago so wordy solutions as in the posts by &nbsp;@Theo 
did not cause protest, &nbsp;now they become &nbsp;INAPPROPRIATE 
for teaching millions of readers of &nbsp;AI.


It is why I work here now checking and re-developing many @Theo' solutions.


Because they &nbsp;SHOULD &nbsp;BE &nbsp;re-developed.