Question 619259
.
Find the center and radius of a sphere, x^2+y^2+z^2-4x+2y-6z+10=0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~



        In the post by @Theo, the center is defined correctly,  while the radius is incorrect.

        I came to fix it.



x^2+y^2+z^2-4x+2y-6z+10 = 0 becomes:
(x^2 - 4x) + (y^2 + 2y) + (z^2 - 6z) = -10 which becomes:
(x-2)^2 + (y+1)^2 + (z-3)^2 = -10 + 4 + 1 + 9 which becomes:
(x-2)^2 + (y+1)^2 + (z-3)^2 = 4.
center is (2,-1,3).
radius = sqrt(4) = 2.


Solved.