Question 1210415
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A neon bulb has the following description:
Current: 1.25 milliamperes.
0.1 watts.
Determine applied voltage.

Check my calculations, please.

Using the following data:
P = power (watts).
I = current (amperes).
E = voltage (volts).
Converting 1.25 milliamperes to amperes (amps.) 1.25 * 1000 = 1250.
P / I
0.1 / 1250 = 0.00008 volts.
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Your calculations are incorrect.


The error is where you convert milliamperes to amperes.


1.25 milliamperes is not   1.25*1000 = 1250 amperes.


1.25 milliamperes is    1.25*0.001 = 0.00125 amperes.


Therefore,  &nbsp;the voltage is  &nbsp;&nbsp;{{{P/I}}} = {{{0.1/0.00125}}} = 80 volts. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>


Solved correctly.



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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;It is useful to know . . . 



Prefix &nbsp;" milli " &nbsp;before a unit's name means &nbsp;" one thousandth " &nbsp;of the unit.


Examples: &nbsp;&nbsp;milligram, &nbsp;millimeter, &nbsp;milliliter, &nbsp;milliampere, . . . and so on.



Prefix &nbsp;" kilo " &nbsp;before a unit's name means &nbsp;" thousand times " &nbsp;the unit.


Examples: &nbsp;&nbsp;kilogram, &nbsp;kilometer, &nbsp;kilovolt, &nbsp;kiloampere, &nbsp;kilowatt, . . . and so on.