Question 1210403
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Working of Log 0.8621 to base 12 with detailed explanation
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        If I understand your writing correctly  (it is written in non-standard form for to be a proper  Math problem)

        you want  (or  " they "  want you)  calculate  logarithm of  0.8621  in base  12.


        @MatLover1 interpreted it differently and gave you another answer.


        I will interpret it literally as I wrote it at the beginning of my post.



<pre>
Use the change of base formula   {{{log(12,a)}}} = {{{log(10,a)/log(10,12)}}}.


Using your standard logarithmic table base 10 or a calculator

    {{{log(10,0.8621)}}} = -0.064442355,   

    {{{log(10,12)}}}     = 1.079181246.


THEREFORE, 

    {{{log(12,0.8621)}}} = {{{log(10,0.8621)/log(10,12)}}} = {{{log((0.8621))/log((12))}} = {{{(-0.064442355)/1.079181246}}} = -0.059714117.


You may round your final answer in this way  

    {{{log(12,0.8621)}}} = -0.05971  (approximately).    <<<---===  <U>ANSWER</U>
</pre>

Solved.



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In standard &nbsp;Math form, &nbsp;your question should be



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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Find the value of logarithm of  &nbsp;0.8621 &nbsp;base 12 using logarithms base 10.


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Then it sounds unambiguously and does not create any distinct interpretations.