Question 1210403

Use the change of base formula: {{{log(b,a) = log(k,a) / log(k,b)}}}


given: {{{log (10,0.8621) }}} to base {{{12}}}


in your case {{{b=10}}},{{{ a=0.8621}}}, {{{k=12}}}


so, you have


{{{log(10,0.8621) = log(12,0.8621)/log(12,10)}}}≈ {{{-0.06/0.927}}}≈ {{{-0.064}}}