Question 1167284
There are 5 honor 'ranks' (10, J, Q, K, A), and each of these ranks has 4 suits. That means there are 5 x 4 = 20 honor cards. 
In addition, there are 8 remaining 'clubs' cards (from 2 to 9), for a total of 20 + 8 = 28 cards satisfying the condition. 
By the fundamental principle of counting, there are 28P4 = 28 x 27 x 26 x 25 = 491,400 ways of dealing one card to each player which is either a clubs or an honor card.