Question 1210396
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You could possibly do a bunch of work "in the background" to set up this problem using a single variable, but it appears to me that would get quite messy.  So let's not try to be clever and just go with separate variables for the costs of each of the three items.<br>
He spent 3/8 of his money on the first purchase and 4/5 of the remaining amount on the second purchase.  After spending 3/8 of his money on the first purchase, he had 5/8 of it left, so when he spent 4/5 of his remaining money on the second purchase that was (4/5)(5/8) = 4/8  of his original money.<br>
The cost of each cupcake is 2/3 the cost of a muffin:
m = cost of a muffin
c = cost of a cupcake
c = (2/3)m<br>
The cost of each piece of waffle is $0.20 more than the cost of a cupcake:
w = cost of a piece of waffle
w = c+0.20 = (2/3)m+0.20<br>
Let x be his original amount of money<br>
The cost of 3 cupcakes and 8 muffins was 3/8 of his original money:<br>
{{{3((2/3)m)+8m=(3/8)x}}}
{{{2m+8m=(3/8)x}}}
{{{10m=(3/8)x}}} [1]<br>
The cost of 15 pieces of waffle was 4/8 of his original money:<br>
{{{15((2/3)m+0.20)=(4/8)x}}}
{{{10m+3=(4/8)x}}} [2]<br>
The given information was such that this approach to solving the problem leads to two equations which are easy to solve. Comparing [1] and [2],<br>
{{{3=(1/8)x}}}
{{{24=x}}}<br>
The amount of money he started with was $24.<br>
From [1], the cost of 10 muffins was 3/8 of $24, or $9.  So the cost of each muffin is $9/10 = $0.90.<br>
ANSWER: $0.90<br>