Question 1210338
<pre>

{{{drawing(4000/17,360, -5,5,-13,4,

line(-4,0,4,0),
line(-4,-6,4,-6),
line(-4,0,-4,-6),
line(4,0,4,-6),
line(-4,0,0,3),
line(4,0,0,3),
line(0,0,0,3),
arc(0,-6,8,-8,180,360),
locate(-4.77,-2.8,6m),
locate(-.5,-5.3,8m),
locate(-2.8,2.2,5m),
locate(0.1,1.9,3m)
)}}}

The triangle at the top has: 
{{{Area=expr(1/2)(base)(height)=expr(1/2)(8)(3)=12m²}}}

Its two slanted sided contribute 2(5m) = 10m to the perimeter.

The rectangle in the middle has:
{{{Area=(base)(height)=(8)(6)=48m²}}}

It's left and right sides contribute 2(6m) = 12m to the perimeter.

The semi-circle at the bottom has diameter 8m and therefor 4m radius:
{{{area=expr(1/2)*(pi*r^2)=expr(1/2)(pi*4^2)=8pi}}} m<sup>2</sup>.

It contributes {{{expr(1/2)*(2*pi*r)=pi*4=4pi}}} m to the circumference.

{{{Area = 12+ 48 + 8pi = 60+8pi}}} m<sup>2</sup>

{{{Perimeter = 10m+12m+4pi = 22+4pi}}} m.

Edwin</pre>