Question 1210338
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Determine the perimeter and area:
https://i.ibb.co/ZzVXsg2g/ED907482-977-D-4-DD4-9636-317-CA1-C38-D45.jpg
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<pre>
The perimeter is (5 + 5) + (6+6) + {{{pi*r}}} = {{{10 + 12 + 3.14159265*(8/2)}}} = 34.5663706 m.


The area is the sum of the areas of two right-angled triangles PLUS the area of the rectangle 
PLUS the area of the semi-circle of the radius 8/2 = 4 m


Right angled triangles are (3-4-5)-triangles. The area of each such triangle is (1/2)*3*4 = 3*2 = 6 m^2.


So, the area under the question is 

    2*6 + 6*8 + {{{(1/2)*pi*r^2}}} = {{{12 + 48 + (1/2)*3.14159265*4^2}}} = 85.1327412 m^2.
</pre>

Solved, with explanations.


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This problem is &nbsp;EXTREMELY &nbsp;simple.


It is of the level &nbsp;" take what you see in the picture, 
and plug the numbers into the simple formula ".


Thinking is not required and is not assumed . . .