Question 1210328
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The other tutor has provided a response showing a very formal mathematical solution.<br>
Here is an informal solution.<br>
Start by buying the minimum required number of uniforms and social clothes.  The cost is 3(360) + 3(600) = 1080+1800 = 2880.<br>
The amount left to spend is 3600-2880 = 720.<br>
You can of course buy only the required minimum number of items, so the first possible way to spend the money is 3 uniforms and 3 social clothes.
(1) (3,3); 2880<br>
With 720 remaining, you can only buy one more uniform at 600 each.  So a second possibility is 4 uniforms and 3 social clothes.
(2) (4,3); 3480<br>
Or, with the remaining 720, you can buy either 1 or 2 more sets of social clothes at 360 each.
(3) (3,4); 3240
(4) (3,5); 3600<br>
ANSWERS:
(a) There are 4 ways to spend the money
(b) Buying 3 uniforms and 5 sets of social clothes uses the largest amount (all) of the available money<br>