Question 1210327
<pre>

The mean is
{{{((3x+2) + 22 + (4x-2) + 23 + 25 + (5x-4) + 29 + 29 + (x^2-7))/9}}}

{{{(x^2 + 12x + 117)/9}}}

The range is

{{{((x^2-7)-(3x+2))= x^2-3x-9}}}

{{{x^2-3x-9=9}}}
{{{x^2-3x-18=0}}}
{{{(x-6)(x+3)=0}}}
x=6; x=-3.

scores aren't negative, so x = 6

The mean is {{{(x^2 + 12 x + 117)/9=(6^2 + 12*6 + 117)/9=225/9=25}}}

So the scores are:

3x+2 = 3(6)+2 = 18+2 = 20 
22 = 22 
4x-2 = 4(6)-2 = 24-2 = 22
23 = 23
25 = 25
5x-4 = 5(6)-4 = 30-4 = 26
29 = 29 
29 = 29 
x<sup>2</sup>-7 = (6)<sup>2</sup>-7 = 36-7 = 29

So they are in non-descending order, not ascending order, as stated.

Since the top 4 scores are 29, 29, 29, 26, all passed, and the applicant 
with 25 failed, the pass mark had to be 26, assuming it had to be a whole
number. 

Edwin</pre>