Question 1210323


{{{x^2-2x+1 = 0}}}........apply the rule {{{a^2-2ab+b^2=(a-b)^2}}}

{{{(x - 1)^2 = 0}}}

solution:

{{{(x - 1) = 0}}}

{{{x =1}}}


{{{ graph( 600, 600, -10, 10, -10, 10, x^2-2x+1) }}}