Question 1210280
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A regular hexagon is below. Solve for the area of the hexagon.
https://ibb.co/dsnSzSLK
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<pre>
The area of any regular hexagon is six times the area of the central equilateral triangle.


In your case, the central equilateral triangle has the side length a = 14 units.


Its height is  h = {{{a*(sqrt(3)/2)}}}.


So, the area of the central equilateral triangle is  

    {{{(1/2)*a*h}}} = {{{(1/2)*a*(a*(sqrt(3))/2))}}} = {{{a^2*(sqrt(3)/4)}}} = {{{14^2*(sqrt(3)/4)}}} = {{{196*(sqrt(3)/4))}}} = {{{49*sqrt(3)}}}  square units.


The area of the hexagon is then  {{{6*49*sqrt(3)}}} = {{{294*sqrt(3)}}} = 509.2229 square units (approximately).    <U>ANSWER</U>
</pre>

Solved.



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A watch has the SAME hexagonal face as the picture to the left. 
If the radius of the circle is 4, then what is the area between the hexagon and circle?
https://ibb.co/ynkmvtbs



<pre>
To solve the second problem, from the area of the hexagon  {{{294*sqrt(3)}}} = 509.2229 square units 
subtract the area of the circle  {{{pi*r^2}}} = {{{3.14159*4^2}}} = 50.26544  square units.


You will get then

    the area of the shaded region = 509.2229 - 50.2644 = 458.9575 square units  (approximately).    <U>ANSWER</U>
</pre>

Solved in full.