Question 117123
{{{x/3-x/6=2}}} Start with the given equation



In order to add these fractions, we need to have a common denominator. Notice how the LCM of the denominators 3 and 6 are 6 (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>). So we need to get the denominator 3 to 6



{{{(2/2)(x/3)-x/6=2}}} Multiply {{{x/3}}} by {{{2/2}}} to get the denominator to 6



{{{2x/6-x/6=2}}} Multiply the fractions



Since we have a common denominator, we can combine the fractions



{{{(2x-x)/6=2}}} Combine the numerators




{{{x/6=2}}} Combine like terms




{{{cross(6)x/cross(6)=2*6}}} Multiply both sides by 6



{{{x=12}}} Multiply



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Answer:

So our answer is {{{x=12}}} 





Check:


{{{x/3-x/6=2}}} Start with the given equation



{{{12/3-12/6=2}}} Plug in the solution  {{{x=12}}} 




{{{4-2=2}}} Divide



{{{2=2}}} Divide.  Since the two sides of the equation are equal, this verifies our answer.