Question 1210253
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Answer: <font color=red>Mean (choice A)</font>



Explanation


You should find the following five number summary<ul><li>min = 800</li><li>Q1 = 950</li><li>median = 1200</li><li>Q3 = 1400</li><li>max = 1600</li></ul>I'll let the student do the scratch work.


Then,
IQR = interquartile range
IQR = Q3 - Q1
IQR = 1400-950
IQR = 450


And
LF = lower fence
LF = Q1 - 1.5*IQR
LF = 950 - 1.5*450
LF = 275
UF = upper fence
UF = Q3 + 1.5*IQR
UF = 1400 + 1.5*450
UF = 2075


If x is a value such that LF < x < UF, then x is not considered an outlier.
Specifically in this problem, if 275 < x < 2075, then x is not an outlier.
Note that min = 800 and max = 1600. Both of which are in the interval mentioned. 
Therefore all values in the set are not considered outliers.


Since we do <u>not</u> have outliers, we can use the <font color=red><u>mean</u></font> as the measure of center.
If there were outliers, then you should use the median. 


The range and interquartile range are <u>never</u> used as a measure of center. 
They measure how spread out the data set is.
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