Question 117020
1/xy + 2/x over 3/y - 1/xy 
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Assume this is the problem:
{{{((1/(xy))+(2/x))/((3/y)-(1/(xy)))}}}
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Covert the fractions in the numerator and denominator into single fractions
{{{((1+2y)/(xy))/((3x-1)/(xy))}}}
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When you divide fractions, you invert the dividing fraction and multiply:
{{{((1+2y))/(xy)}}} * {{{(xy)/((3x-1))}}} = {{{((1+2y))/((3x-1))}}}; note that the xy's cancel
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