Question 1210236
.


One look at this equation is enough to see that it has no solutions in real numbers.


Indeed,   for any real value of  x,   {{{2^(2x-3)}}}   is less  than   {{{2^(2x-2)}}}.


So,  the difference   {{{2^(2x-3)}}} - {{{2^(2x-2)}}}   is always negative.


When you subtract  1  from this negative number,  you get negative number lesser than  -1.


Thus,  left side of the equation can not be equal to zero.