Question 1210236
<pre>
{{{2^(2x-3) - 2^(2x-2) - 1 = 0}}}

{{{2^(2x)*2^(-3) - 2^(2x)*2^(-2) - 1=0}}}

let {{{y=2^(2x)}}}

{{{y*2^(-3) - y*2^(-2) - 1=0}}}

{{{y^""/2^3 - y^""/2^2 - 1=0}}}

{{{y/8 - y/4 - 8=0}}}

{{{y-2y-8=0}}}

{{{-y-8=0}}}

{{{y+8=0}}}

{{{2^(2x)+8=0}}}

{{{2^(2x) = -8}}}

There is no real solution.  Do you want complex solution(s)?

Normally if complex solutions are wanted, the variable is z, not x.

Edwin</pre>