Question 864702
<pre>

This problem was posted over a decade ago (2014) and solved by a nice lady tutor
back then whose screen name was ewatrrr(24785).  Notice she has solved it correctly.

She is thinking of your randomly choosing them one at a time.

The probability of your successfully choosing a silver earring the first time is
2 out of 4, or (2/4). 

If you are successful on the first choice, then there are 3 earrings left in the
box, the other silver one, and the 2 gold ones.
  
The probability is then 1 out of 3 (1/3) of drawing the other silver earring.

Therefore the desired probability is, as she so correctly gives,

{{{(2/4)(1/3) = 2/12 = 1/6}}}.

Edwin</pre>