Question 1168301
Let's break down each part of the problem:

**2.1 On Wednesday:**

* **Price per bottle:** $11.50
* **Total revenue:** $2530

To find the number of bottles sold, we divide the total revenue by the price per bottle:

Number of bottles = Total revenue / Price per bottle
Number of bottles = $2530 / $11.50 = 220 bottles

Since each bottle contains 5 litres of water, the total litres of water sold on Wednesday is:

Total litres = Number of bottles × Litres per bottle
Total litres = 220 bottles × 5 litres/bottle = 1100 litres

**Answer to 2.1: 1100 litres of water were sold on Wednesday.**

**2.2 On Thursday:**

* **Price per bottle:** $11
* **Total revenue:** $x

To find the number of bottles sold, we divide the total revenue by the price per bottle:

Number of bottles = Total revenue / Price per bottle
Number of bottles = $x / $11 = \frac{x}{11}$ bottles

Since each bottle contains 5 litres of water, the total litres of water sold on Thursday is:

Total litres = Number of bottles × Litres per bottle
Total litres = $\frac{x}{11}$ bottles × 5 litres/bottle = $\frac{5x}{11}$ litres

**Answer to 2.2: $\frac{5x}{11}$ litres of water were sold on Thursday.**

**2.3 On Friday:**

* **Price per bottle:** $9
* **Total revenue:** $(x - 20)$

To find the number of bottles sold, we divide the total revenue by the price per bottle:

Number of bottles = Total revenue / Price per bottle
Number of bottles = $\frac{(x - 20)}{9}$ bottles

Since each bottle contains 5 litres of water, the total litres of water sold on Friday is:

Total litres = Number of bottles × Litres per bottle
Total litres = $\frac{(x - 20)}{9}$ bottles × 5 litres/bottle = $\frac{5(x - 20)}{9}$ litres

**Answer to 2.3: $\frac{5(x - 20)}{9}$ litres of water were sold on Friday.**

**2.4 If the number of bottles sold on Thursday equals the number of bottles sold on Friday:**

From our answers to 2.2 and 2.3, the number of bottles sold on Thursday is $\frac{x}{11}$ and the number of bottles sold on Friday is $\frac{x - 20}{9}$. We are given that these are equal:

$\frac{x}{11} = \frac{x - 20}{9}$

To solve for x, we can cross-multiply:

$9x = 11(x - 20)$
$9x = 11x - 220$

Now, isolate x:

$220 = 11x - 9x$
$220 = 2x$
$x = \frac{220}{2}$
$x = 110$

Now that we have the value of x, we can find the number of bottles sold on Thursday and Friday:

Number of bottles on Thursday = $\frac{x}{11} = \frac{110}{11} = 10$ bottles

Number of bottles on Friday = $\frac{x - 20}{9} = \frac{110 - 20}{9} = \frac{90}{9} = 10$ bottles

**Answer to 2.4: 10 bottles of water were sold on each of these two days.**