<PRE><B>Question 1210213</B>
&lt;br&gt;
The AI solution from the other &quot;tutor&quot; involves finding the number of ways of splitting the 8 cards into 4 piles of 2 card each.&lt;br&gt;
The way I read the problem, the 8 cards have already been split into 4 piles of 2 cards each; the question is the probability that each of those piles of 2 cards contains an ace.&lt;br&gt;
So the problem is only asking the probability that the 4 aces get in separate piles.&lt;br&gt;
The first ace can be in any of the 4 piles -- probability 4/4
The second ace can be in any of the 3 remaining piles -- probability 3/4
The third ace can be in any of the 2 remaining piles -- probability 2/4
The fourth ace can be in any of the 1 remaining piles -- probability 1/4&lt;br&gt;
The probability that the 4 aces are in different piles is&lt;br&gt;
{{{(4/4)(3/4)(2/4)(1/4)=24/256=3/32}}}&lt;br&gt;
It doesn&#39;t matter which king gets with which ace, so that is the final answer to the problem.&lt;br&gt;
ANSWER: 3/32&lt;br&gt;

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