Question 1210208
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Tutor ikleyn has recently been posting wrong answers to relatively simple problems and posting disparaging comments about solutions that are correct, then having to eat crow and apologize when she realizes her solution is wrong.  Sad....<br>
This is a quite basic probability problem.  We need to choose 2 of the 4 earrings, and the desired outcome is that we choose 2 of the 2 silver hoop earrings and 0 of the 2 gold hoop earrings.  Using the basic definition  of probability, the probability is<br>
{{{(C(2,2)*C(2,0))/C(4,2)=(1*1)/6=1/6}}}<br>
We can also get that result analyzing the problem as choosing one earring at a time.<br>
The probability that the first earring is silver hoop is 2/4; then the probability that the second earring is the other silver hoop is 1/3.  The probability that they are both silver hoop is then<br>
{{{(2/4)(1/3)=1/6}}}<br>