Question 1210198
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The number of 13-card hands is "52 choose 13", which (rounded) is 6.35x10^11.<br>
The number of 13-card hands that contains none of a particular one of the 4 suits is "39 choose 13", which is (rounded) 8.12x10^9.<br>
The probability that a 13-card hand contains none of one suit is then<br>
{{{(4*C(39,13))/C(52,13)}}}<br>
which is 0.05116379....  As a percentage rounded to a tenth of a percent, that is...<br>
ANSWER: 5.1%<br>