Question 1210199
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The sequence has 8 terms; each term is an integer from 1 to 8 inclusive; and the sequence must contain each of those integers at least once.<br>
That means the sequence contains each of those integers EXACTLY once.  So the number of sequences is simply the number of arrangements of the 8 integers, which is 8! = 40,320.<br>
ANSWER: 40,320<br>