Question 1210194
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At a meeting, two scientists, two mathematicians, two historians, and two artists are to be seated around a circular table.  
In how many ways can they be seated so that all four pairs of people from the same discipline are seated together?
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        Since you came with pairs of persons around a round table,  it means  (at the normal teaching process)

        that you are just familiar with the basic cases for such problems.


        So,  I will not repeat the basics,  but will simply give a short form solution.



<pre>
In this problem, we have 4 pairs as the units/items.


4 items can be placed around a circle in (4-1)! = 3! = 6 different way (circular permutations).


In addition, one permutation is possible inside each pair.


It gives, in total,   {{{2^4*3!}}} = 16*6 = 96  different circular placements in this problem.    <U>ANSWER</U>
</pre>

Solved.