Question 1210190
Let's break down this problem step by step.

**1. Visualize the Path**

* Chris starts at a point (the cone).
* He walks 40 meters west.
* He turns 30° to his right (northward direction) and walks 20 meters.

We can represent this as a triangle. Let's label the points:

* **A:** The location of the cone.
* **B:** The point 40 meters west of the cone.
* **C:** Chris's final location.

**2. Apply the Law of Cosines**

We need to find the distance AC. We know:

* AB = 40 meters
* BC = 20 meters
* Angle ABC = 180° - 30° = 150°

The Law of Cosines states:

AC² = AB² + BC² - 2(AB)(BC)cos(∠ABC)

**3. Plug in the Values**

AC² = 40² + 20² - 2(40)(20)cos(150°)

AC² = 1600 + 400 - 1600cos(150°)

**4. Evaluate cos(150°)**

* cos(150°) = -√3 / 2 ≈ -0.866

AC² = 2000 - 1600(-0.866)

AC² = 2000 + 1385.6

AC² = 3385.6

**5. Calculate AC**

AC = √3385.6 ≈ 58.186

**6. Round to the Nearest Whole Number**

AC ≈ 58 meters

**Therefore, Chris is approximately 58 meters from the cone.**