Question 1210157
Let's solve this problem step by step.

**1. Probability of the First Marble Being Green**

* There are 7 green marbles and 6 red marbles, for a total of 13 marbles.
* The probability of drawing a green marble is:
    * P(Green first) = 7/13

**2. Probability of the Second Marble Being Red**

* Since the first marble is returned to the basket, the total number of marbles remains 13.
* The probability of drawing a red marble is:
    * P(Red second) = 6/13

**3. Probability of Both Events Occurring**

* Since the events are independent (because the first marble is returned), we multiply the probabilities:
    * P(Green first and Red second) = P(Green first) * P(Red second)
    * P(Green first and Red second) = (7/13) * (6/13) = 42/169

**Therefore, the probability that the first marble is green and the second marble is red is 42/169.**