Question 1210150
<pre>

No sane algebra teacher would assign an equation to solve containing a term
written as {{{3/3}}}.  But many a student leaves off parentheses, whenever a
numerator or denominator contains more than one number or one letter. So they
probably typed 

{{{(2x+3)/3}}} incorrectly as 2x+3/3, when it should have been typed as (2x+3)/3.

This problem either was intended to be:

{{{(3x+2)/5-(2x+3)/3=3}}} or possibly {{{3x+2/5-(2x+3)/3=3}}}.  Most likely
the first one:

{{{(3x+2)/5-(2x+3)/3=3}}}

Multiply each term by the LCD of 15 to clear of fractions.

{{{15*expr((3x+2)/5)-15*expr((2x+3)/3)=15*3}}}

{{{3*(3x+2)-5*(2x+3)=45}}}

Distribute to remove the parentheses:

{{{9x+6-10x-15= 45}}}

Collect like terms:

{{{-x-9=45}}}

Add 9 to both sides:

{{{-x-9+9=45+9}}}

{{{-x = 54}}}

Multiply (or divide) both sides by -1

{{{x = -54}}}

Edwin</pre>