Question 1170030
Let's break down this problem step by step.

**1. List All Possible Outcomes:**

The urn contains: B1, B2, W1, W2, W3.

Since we draw a ball, replace it, and draw again, there are 5 possible outcomes for the first draw and 5 for the second draw. This gives us 5 * 5 = 25 possible outcomes.

The possible outcomes are:

* B1B1, B1B2, B1W1, B1W2, B1W3
* B2B1, B2B2, B2W1, B2W2, B2W3
* W1B1, W1B2, W1W1, W1W2, W1W3
* W2B1, W2B2, W2W1, W2W2, W2W3
* W3B1, W3B2, W3W1, W3W2, W3W3

**2. Event: First Ball Drawn is Blue**

* Count the outcomes where the first ball is blue:
    * B1B1, B1B2, B1W1, B1W2, B1W3
    * B2B1, B2B2, B2W1, B2W2, B2W3
* Total outcomes in this event: 10

* Probability of the event:
    * Probability = (Number of outcomes in the event) / (Total number of outcomes)
    * Probability = 10 / 25 = 2/5 = 0.4

**(a) Answers:**

* Total: 10
* Probability: 2/5 or 0.4

**3. Event: Only White Balls Are Drawn**

* Count the outcomes where both balls drawn are white:
    * W1W1, W1W2, W1W3
    * W2W1, W2W2, W2W3
    * W3W1, W3W2, W3W3
* Total outcomes in this event: 9

* Probability of the event:
    * Probability = (Number of outcomes in the event) / (Total number of outcomes)
    * Probability = 9 / 25 = 0.36

**(b) Answers:**

* Total: 9
* Probability: 9/25 or 0.36