Question 1209958
<pre>
Do you have a TI-84 Plus?

Let's do the second one first, as it's more straightforward. 

2nd 
vars
Scroll down to B:binomcdf
enter

        binomcdf
trials:14
p:0.55
x value:3
Paste

[The reason for 3 in x-value is because the calculator understands 3 as
 "3 or less", which is the same as "fewer than 4".

Scroll to Paste
enter
you see binomcdf(14,0.55,3)
enter

0.011430528

-----------------

The first one:

You will have to first calculate the probability of the complement event,
then subtract from 1.

The complement of " at least 3 " is " 2 or fewer "

2nd 
vars
Scroll down to B:binomcdf
enter

        binomcdf
trials:14
p:0.55
x value:2
Paste

[The reason for 2 in x-value is because the calculator understands 2 as
 "2 or less"

Scroll to Paste
enter
you see binomcdf(14,0.55,3)
enter

0.002150974  

But that's not the answer. You must subtract from 1.

1 - 0.002150974

0.997849026

Round to 4 decimal places.

Edwin</pre>