Question 17641
Let Louise's age =x
and Todd's age =y
as per question x+y = 34   -----eq(1)
five years ago Louise's age  was = x-5
and Todd's age was =y-5

and 2(x-5)+3(y-5)=61   
or 2x-10+3y-15=61
or 2x+3y-25=61
or 2x+3y=61+25=86-------eq(2)
solving eq(1) and eq(2)we have
i.e eq(1)-eq(2)
2x+2y=68
-2x-3y=-86
-----------
-y =-18
or y =18
so x = 34-18=16
so Todd's age =18 years
and Louise's age =16 years