Question 1171398
Let's break down this probability problem:

* **Total Cards:** An ordinary deck has 52 cards.
* **Red Cards:** There are 26 red cards (13 hearts and 13 diamonds).
* **Hearts:** There are 13 hearts.

We're given that the first card dealt is a red card. We want to find the probability that it was also a heart. This is a conditional probability.

* **P(Heart | Red):** The probability of the card being a heart, given that it's red.

We can use the formula for conditional probability:

* P(Heart | Red) = P(Heart and Red) / P(Red)

* **P(Heart and Red):** Since all hearts are red, P(Heart and Red) is the same as P(Heart).
    * P(Heart) = 13/52

* **P(Red):** The probability of drawing a red card.
    * P(Red) = 26/52

Now, plug these values into the conditional probability formula:

* P(Heart | Red) = (13/52) / (26/52)

To simplify, multiply the numerator by the reciprocal of the denominator:

* P(Heart | Red) = (13/52) * (52/26)

The 52's cancel out:

* P(Heart | Red) = 13/26

Simplify the fraction:

* P(Heart | Red) = 1/2

Therefore, the probability that the card was also a heart is 1/2.