Question 1171440
Let's solve this problem using the properties of the normal distribution.

**1. Define the Variables**

* Mean (μ) = 153 cm
* Standard deviation (σ) = 12 cm
* We want to find the probability that a woman's height (X) is less than 150 cm, i.e., P(X < 150).

**2. Calculate the Z-score**

The Z-score represents how many standard deviations a value is from the mean. It's calculated using the formula:

* Z = (X - μ) / σ

In our case:

* Z = (150 - 153) / 12
* Z = -3 / 12
* Z = -0.25

**3. Find the Probability Using the Z-table or Calculator**

We need to find the probability P(Z < -0.25). This is the area under the standard normal distribution curve to the left of Z = -0.25.

You can find this probability using:

* A standard normal distribution table (Z-table)
* A calculator with statistical functions
* An online normal distribution calculator

Using a Z-table or calculator, you will find:

* P(Z < -0.25) ≈ 0.4013

**4. Interpret the Result**

The probability that a randomly selected Southeast Asian woman's height is less than 150 cm is approximately 0.4013, or 40.13%.

**Therefore, the probability is approximately 0.4013.**