Question 116999
Solve by graphing.
Actually these two equations have the same slope, therefore they are parallel lines and can't be solved by graphing or any other way.
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However this is the procedure and you will see what I mean:
Take one equation at a time:
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Put in slope/intercept form
2x = y + 1
Subtract 1 from both sides
2x - 1 = y
We can also write in the more familiar form:
y = 2x - 1
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Make a table to plot this as a graph, you only need 2 points, however here are 3
Let x = -3
Substitute -3 for x in the above equation and find y
y = 2x - 1
y = 2(-3)- 1
y = -6 - 1
y = -7
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The table:
 x | y
------
-3 |-7

do the same with x = 0
y = 2(0) - 1
y = -1
and
for x = +3
y = 2(3) - 1
y = +6 -1 
y = + 5
the table now
 x| y
-----
-3|-7
 0|-1
+3|+5
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Plot these point on a standard +/- 10 graph, should look like this:
{{{ graph( 300, 200, -6, 5, -10, 10, 2x-1) }}}
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Do exactly the same with this equation and plot on the same graph
2x - y = 5 
-y = -2x + 5; subtracted 2x from both sides
y = +2x - 5; y always has to be positive, multiplied by -1
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You can see now that the two equations have the same slope (2)
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Plot this one using the values for x, -2, 0 +3
Substitute these values for x in the above equation,
 x| y
------
-2|-9
 0|-5
+3|+1
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{{{ graph( 300, 200, -6, 5, -10, 10, 2x-1,2x-5) }}}
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Anyway, if the graph of two equation intersect at some point, the x/y value of that point is the solution. 
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