Question 1172912
Absolutely, let's break down this probability problem step-by-step.

**a. Sample Space**

First, let's assign labels to the applicants:

* Males: B1, B2, B3 (Blue tickets)
* Females: R1, R2 (Red tickets)

We need to find all possible pairs of applicants that can be interviewed. We can list them systematically:

* B1, B2
* B1, B3
* B1, R1
* B1, R2
* B2, B3
* B2, R1
* B2, R2
* B3, R1
* B3, R2
* R1, R2

Therefore, the sample space (S) is:

S = { (B1, B2), (B1, B3), (B1, R1), (B1, R2), (B2, B3), (B2, R1), (B2, R2), (B3, R1), (B3, R2), (R1, R2) }

**b. Event: At Least One Male is Interviewed**

Let's identify the outcomes in the sample space where at least one male is interviewed:

* (B1, B2)
* (B1, B3)
* (B1, R1)
* (B1, R2)
* (B2, B3)
* (B2, R1)
* (B2, R2)
* (B3, R1)
* (B3, R2)

Let's call this event "M".

Therefore:

M = { (B1, B2), (B1, B3), (B1, R1), (B1, R2), (B2, B3), (B2, R1), (B2, R2), (B3, R1), (B3, R2) }