Question 1209818
Let's find the first few terms of the sequence:
* $a_0 = 1$
* $a_2 = 2$
* $a_{n+2} = \frac{a_{n+1}}{a_n}$

We need to find $a_1$. We can use the formula with $n=0$:
$a_2 = \frac{a_1}{a_0}$
$2 = \frac{a_1}{1}$
$a_1 = 2$

Now, let's find more terms:
* $a_3 = \frac{a_2}{a_1} = \frac{2}{2} = 1$
* $a_4 = \frac{a_3}{a_2} = \frac{1}{2}$
* $a_5 = \frac{a_4}{a_3} = \frac{1/2}{1} = \frac{1}{2}$
* $a_6 = \frac{a_5}{a_4} = \frac{1/2}{1/2} = 1$
* $a_7 = \frac{a_6}{a_5} = \frac{1}{1/2} = 2$
* $a_8 = \frac{a_7}{a_6} = \frac{2}{1} = 2$
* $a_9 = \frac{a_8}{a_7} = \frac{2}{2} = 1$
* $a_{10} = \frac{a_9}{a_8} = \frac{1}{2}$
* $a_{11} = \frac{a_{10}}{a_9} = \frac{1/2}{1} = \frac{1}{2}$
* $a_{12} = \frac{a_{11}}{a_{10}} = \frac{1/2}{1/2} = 1$

The sequence is periodic with period 6: 1, 2, 2, 1, 1/2, 1/2, 1, 2, 2, 1, 1/2, 1/2, ...

The sum of the terms in one period is:
$1 + 2 + 2 + 1 + \frac{1}{2} + \frac{1}{2} = 7$

We want to find $a_0 + a_1 + a_2 + \dots + a_{100}$.
Since the period is 6, we can divide 101 by 6:
$101 = 16 \cdot 6 + 5$
So there are 16 full periods and 5 remaining terms.
The sum of the 16 full periods is $16 \cdot 7 = 112$.
The remaining 5 terms are $a_{96}, a_{97}, a_{98}, a_{99}, a_{100}$, which are the same as $a_0, a_1, a_2, a_3, a_4$:
$1, 2, 2, 1, \frac{1}{2}$
The sum of these 5 terms is $1 + 2 + 2 + 1 + \frac{1}{2} = \frac{13}{2} = 6.5$.

Therefore, the sum of the first 101 terms is:
$112 + \frac{13}{2} = \frac{224}{2} + \frac{13}{2} = \frac{237}{2} = 118.5$

Final Answer: The final answer is $\boxed{118.5}$