Question 116976

{{{b^2x^2+a^2y^2=a^2b^2}}} Start with the given equation




{{{b^2x^2=a^2b^2-a^2y^2}}}Subtract a^2y^2 from both sides



{{{x^2=(a^2b^2-a^2y^2)/b^2}}} Divide both sides by {{{b^2}}}



{{{x=sqrt((a^2b^2-a^2y^2)/b^2)}}} Take the square root of both sides




{{{x=sqrt((a^2b^2-a^2y^2))/b}}} Simplify




{{{x=sqrt(a^2(b^2-y^2))/b}}} Factor out {{{a^2}}}




{{{x=a*sqrt(b^2-y^2)/b}}} Simplify