Question 1209788
Here's how we can solve this problem:

Let $q$ be the number of quarters and $d$ be the number of dimes.

Since Roberta has 5 more dimes than quarters, we have the equation:

$d = q + 5$

The total number of coins is 25, so we have:

$q + d = 25$

Substituting the first equation into the second equation, we get:

$q + (q + 5) = 25$

Combining like terms, we have:

$2q + 5 = 25$

Subtracting 5 from both sides, we get:

$2q = 20$

Dividing both sides by 2, we find:

$q = 10$

Substituting this value back into the equation $d = q + 5$, we find:

$d = 10 + 5 = 15$

So, Roberta has 10 quarters and 15 dimes.

We can check our answer by verifying that the total amount of money is $4:

$0.25(10) + $0.10(15) = $2.50 + $1.50 = $4.00

Therefore, our answer is correct.