Question 1209770
.
Find all (real or nonreal) x satisfying
(x - 3)^4 + (x - 5)^4 = -8 + 6(x - 3)(x - 5)^3 - 11(x - 3)^3 (x - 5).
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            The solution in the post by @CPhill is   {{{highlight(highlight(INCORRECT))}}}.



@CPhill deduced this equation to 


<pre>
    7a^4 + 34a^3 + 12a^2 - 34a + 5 = 0

    **2. Factor the Equation:**

    Notice that the coefficients are symmetric.    <<<---=== This is WRONG: coefficients are not symmetric,
    This suggests that we can factor by grouping.  <<<---===  Therefore, this method of reducing to quadratic equation 
                                                              DOES NOT work and, therefore, is INCORRECT.

    Let's divide by a^2:

    7a^2 + 34a + 12 - 34/a + 5/a^2 = 0
    7(a^2 + 5/7a^2) + 34(a - 1/a) + 12 = 0

    Let b = a - 1/a. Then b^2 = a^2 - 2 + 1/a^2, so a^2 + 1/a^2 = b^2 + 2

    7(b^2 + 2) + 34b + 12 = 0
    7b^2 + 14 + 34b + 12 = 0
    7b^2 + 34b + 26 = 0                             <<<---===  INMCORRECT REDUCTION.
</pre>

But this reduction to the quadratic equation is INCORRECT.

Coefficients of this equation are NOT symmetric; therefore, this method of reduction 
to quadratic equation is INCORRECT.


Everything what follows in the post by @CPhill, is IRRELEVANT AND INCORRECT.


<H3>This "solution" from @CPhill is the total, global and fatal deception of a reader.</H3>

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   &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;THE &nbsp;PROBLEM &nbsp;IS &nbsp;NOT &nbsp;SOLVED.


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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Regarding the post by @CPhill . . . 



Keep in mind that @CPhill is a pseudonym for the Google artificial intelligence.


The artificial intelligence is like a baby now. It is in the experimental stage 
of development and can make mistakes and produce nonsense without any embarrassment.



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;It has no feeling of shame - it is shameless.



This time, again, &nbsp;it made an error.



Although the @CPhill' solution are copy-paste &nbsp;Google &nbsp;AI solutions, &nbsp;there is one essential difference.


Every time, &nbsp;Google &nbsp;AI &nbsp;makes a note at the end of its solutions that &nbsp;Google &nbsp;AI &nbsp;is experimental
and can make errors/mistakes.


All @CPhill' solutions are copy-paste of &nbsp;Google &nbsp;AI &nbsp;solutions, with one difference:
@PChill never makes this notice and never says that his solutions are copy-past that of Google.
So, he NEVER SAYS TRUTH.


Every time, &nbsp;@CPhill embarrassed to tell the truth.

But I am not embarrassing to tell the truth, &nbsp;as it is my duty at this forum.



And the last my comment.


When you obtain such posts from @CPhill, &nbsp;remember, &nbsp;that &nbsp;NOBODY &nbsp;is responsible for their correctness, 
until the specialists and experts will check and confirm their correctness.


Without it, &nbsp;their reliability is &nbsp;ZERO and their creadability is &nbsp;ZERO, &nbsp;too.



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    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;How to solve this problem.



Reduce the given polynomial to the standard form.


This polynomial has no rational roots that can be found using Rational Root Test.


At this point, there are 3 ways to follow.


First way is to use formula for quartic polynomial equation.
This way is not practical and it is never used in school Math assignments.


Second way is to use online solvers, for example, at this site
https://www.mathportal.org/calculators/polynomials-solvers/polynomial-roots-calculator.php
They will provide all real and complex roots.


Third way is to use graphic calculator or an appropriate plotting tools,
for example, at this site (free of charge)
www.desmos.com/calculator
It will provide real roots.


Have a nice day!


<H2>Obtaining such "solutions" from @CPhill, 
I would not trust to any his word and/or number.<H2><H3>The computer program, which uses this "Artificial intelligence,"
works based on the principle "to deceive a reader at any cost".<H3>